5x^2-9x-1136=0

Solution for 5x^2-9x-1136=0 equation:

5x^2-9x-1136=0

a = 5; b = -9; c = -1136;
Δ = b2-4ac
Δ = -92-4·5·(-1136)
Δ = 22801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22801}=151$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-151}{2*5}=\frac{-142}{10}
=-14+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+151}{2*5}=\frac{160}{10}
=16
$